2[g(b)+1]=x-2x^2

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Solution for 2[g(b)+1]=x-2x^2 equation:


Simplifying
2[g(b) + 1] = x + -2x2

Multiply g * b
2[bg + 1] = x + -2x2

Reorder the terms:
2[1 + bg] = x + -2x2
[1 * 2 + bg * 2] = x + -2x2
[2 + 2bg] = x + -2x2

Solving
2 + 2bg = x + -2x2

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '-2' to each side of the equation.
2 + -2 + 2bg = x + -2 + -2x2

Combine like terms: 2 + -2 = 0
0 + 2bg = x + -2 + -2x2
2bg = x + -2 + -2x2

Reorder the terms:
2bg = -2 + x + -2x2

Divide each side by '2g'.
b = -1g-1 + 0.5g-1x + -1g-1x2

Simplifying
b = -1g-1 + 0.5g-1x + -1g-1x2

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